(4x+3)(3x^2-20x-7)=0

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Solution for (4x+3)(3x^2-20x-7)=0 equation: 


Simplifying
(4x + 3)(3x2 + -20x + -7) = 0

Reorder the terms:
(3 + 4x)(3x2 + -20x + -7) = 0

Reorder the terms:
(3 + 4x)(-7 + -20x + 3x2) = 0

Multiply (3 + 4x) * (-7 + -20x + 3x2)
(3(-7 + -20x + 3x2) + 4x * (-7 + -20x + 3x2)) = 0
((-7 * 3 + -20x * 3 + 3x2 * 3) + 4x * (-7 + -20x + 3x2)) = 0
((-21 + -60x + 9x2) + 4x * (-7 + -20x + 3x2)) = 0
(-21 + -60x + 9x2 + (-7 * 4x + -20x * 4x + 3x2 * 4x)) = 0
(-21 + -60x + 9x2 + (-28x + -80x2 + 12x3)) = 0

Reorder the terms:
(-21 + -60x + -28x + 9x2 + -80x2 + 12x3) = 0

Combine like terms: -60x + -28x = -88x
(-21 + -88x + 9x2 + -80x2 + 12x3) = 0

Combine like terms: 9x2 + -80x2 = -71x2
(-21 + -88x + -71x2 + 12x3) = 0

Solving
-21 + -88x + -71x2 + 12x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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